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H(x)=(g o f)(x)=1/(x+3)^2 which of the fallowing could be a possible decomposition of h(x)? A. f(x)=1/x^2;g(x)=x+3 B. f(x)=x+3; g(x)=1/x^2 C.f(x)=x^2; g(x)=x+3 D. f(x)=1/x;g(x)=x+3

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2 Answers

1 vote
f(x)=x+3; g(x)=1/x^2

If you take B f(x)=x+3 g(x)=1/x^2 plug the f(x) into the g(x) formula (in other words, f(x) becomes the x for g) g(x)=1/x^2 g(x)=1/(x+3)^2
User Greg Samson
by
7.5k points
6 votes
I am pretty sure that the only possibl decomposition of the finction represented above is being revealed by the second option - B. f(x)=x+3; g(x)=1/x^2. I choose this one because I plugged the f(x) into the g(x) and that's what I got :
g(x)=1/x^2 g(x)=1/(x+3)^2
User Ishuar
by
7.6k points
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