Answer:
Explanation:
P(t)=130t -0.4t^4 +1200
The population will be max when first differential of p(t) =0
So p'(t) =130-1.6t^3=0
1.6t^3=130
t^3 =130/1.6
t^3 =81.25
t = cube root of 81.25
t =4.3 months
P(max) =130(4.3) -0.4(4.3)^4 +1200
= 559-136.75+1200
=1622
Population will disappear when p(t) =0