Question

Ben has $3.40 consisting of quarters and dimes. How many coins of each kind does he have if he has 22 coins?

Show a system of equation to represent the word problem.

Answer 1

There are 8 quarters and 14 dimes.

Explanation:

Let there are x quarters.

and y dimes.

Also as we know,

1 quarter= 0.25 dollar

Hence, x quarter= $ 0.25x

and 1 dime= $ 0.10

Hence, y dimes= $ 0.10y

• Ben has $3.40 consisting of quarters and dimes.

This means that:

0.25x+0.10y=3.40

Also, in non-decimal form it could be written as:

25x+10y=340

• He has 22 coins

This means that:

x+y=22

Now on solving it graphically we see what is the point of intersection of the two lines or system of linear equations.

We get the point of intersection as: (8,14)

i.e. x=8 and y=14

Hence, there are 8 quarters.

and 14 dimes.

Answer 2

got d + q = 22 and 10d + 25q = 340??