State the y-coordinate of the y-intercept for the function below. ƒ(x)=x^3-x^2-x+1 ...?

asked Oct 7, 2017 58.0k views

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State the y-coordinate of the y-intercept for the function below.

ƒ(x)=x^3-x^2-x+1 ...?

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1 vote

Answer:

Explanation:

Answer is 1 for Apex Precal

Flyingace answered Oct 8, 2017

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when y intercpets, x = 0
so here,

ƒ(x)=x^3-x^2-x+1
ƒ(x)=(0)^3-(0)^2-0+1
ƒ(x)= +1

Noam Manos answered Oct 12, 2017

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