Question

You have a small block of gallium that has a mass of 2.5g. How much heat was required to raise its temperature from 22.0 Celsius to 29.8 Celsius?

Answer 1

To solve this question, we have to use the formula of heat transfer which is given as

`\begin{gathered} Q=mc\Delta\theta \\ m\text{ = mass} \\ c\text{ = specific heat capacity} \\ \Delta\theta\text{ = change in temperature} \end{gathered}`

Let us define our variables and proceed to substitute the values in the equation.

`\begin{gathered} m\text{ = 2.5} \\ c\text{ = 0.37J/}g\text{ K} \\ \Delta\theta\text{ = (29.8 - 22.0) = 7.8} \end{gathered}`

Substituting the values, we would have

`\begin{gathered} Q=mc\Delta\theta \\ Q=2.5\cdot0.37\cdot7.8=7.215J \end{gathered}`

From the calculations above, the heat transfer in the block was 7.215J