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What are the coordinates of the focus of the conic section shown below? y^2-4x+4y-4=0 ...?
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What are the coordinates of the focus of the conic section shown below?

y^2-4x+4y-4=0



...?

User Ndogac
by
7.3k points

2 Answers

2 votes

Answer:

(-1,-2) is the correct answer

Explanation:

User Lalebarde
by
7.6k points
4 votes
the answer is
y^2-4x+4y-4=y^2+4y-4x-4=(y+2)²-4x - 8= 0
it is the same of x + 2 = (1/4 ) (y+2)²

the main formula is x-h= a (y-k)² so h=-2, k= - 2 and a=1/4
User Thanos Tintinidis
by
7.9k points
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