Question

A ball is thrown from an initial height of 3 ft with an initial upward velocity of 27ft/s The balls height h (in feet) after t seconds is given by the following. h=3+27t-16t^2. Find all values of t for which the balls height is 13 ft. ...?

Answer 1

t = 0.55 s and t = 1.14 s

Step-by-step explanation:

as we know that height in terms of time is given as

`h = 3 + 27t - 16 t^2`

now we have to find the time at which its height is h = 13 ft

so here we can say

`13 = 3 + 27 t - 16 t^2`

`16 t^2 - 27 t + 10 = 0`

`t = (27 \pm √(27^2 - 4(16)(10)))/(2(16))`

`t = (27 \pm 9.43)/(32)`

`t = 1.14, 0.55`

so it will be at h = 13 ft height at t = 0.55 s and t = 1.14 s