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Prove the trigonometric identity: (csc^2x)/(cotx)=cscxsecx ...?
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4 votes
Prove the trigonometric identity:
(csc^2x)/(cotx)=cscxsecx ...?

User Solamour
by
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1 Answer

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cscx = 1 / sinx, so csc^2x = 1/ sin²x, and cotx=cosx / sinx
so (csc^2x)/(cotx)=(1/ sin²x) (sinx/cosx) = 1/(sinxcosx) = 1/sinx 1/cosx
finally
(csc^2x)/(cotx)=cscxsecx
User Sootah
by
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