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Help Please? Factor Completely: 2x2 − 32

Prime
2(x2 − 16)
2(x + 4)(x + 4)
2(x + 4)(x − 4) ...?

2 Answers

1 vote

Answer:

D. 2(x + 4)(x − 4)

Explanation:

User Nada
by
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0 votes

Answer:

Option 4th is correct


2 \cdot (x-4)(x+4)

Explanation:

Using difference of square:


a^2-b^2=(a-b)(a+b)

GCF is the largest number that divide the given polynomial or expression.

Given the expression:


2x^2-32

We have to completely factor the expression.

GCF of
2x^2 and 32 is, 2

then;


2 \cdot (x^2-16)

Using difference of square


2 \cdot (x-4)(x+4)

therefore, the completely factor of
2x^2-32 is,

2 \cdot (x-4)(x+4)

User JomanJi
by
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