Answer:
743.41 feet.
Explanation:
In this question it is given that height of the tower OS is 175 feet and angle of depression ∠ASB = 13°15'
angle of depression to the boat B will be equal to the angle of elevation "∠B"
Now ∠ASB = 13°15' ≈ 13° +
°
= 13° + (0.25)°
= 13.25°
Now tan ∠B =

tan (13.25) =

x =

= 743.41 feet.
Motorboat is 743.41 feet far from the shore.