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SOLVE. (2ax + 1/2 bx)2 ...?

User Ivan Peric
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1 Answer

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The answer is 4a²x² + 2abx² + 1/4b²x².

This is the square of the sum. The general formula is:
(m + n)² = m² + 2mn + n²

In our case, m = 2ax and n = 1/2bx.
So:
(2ax + 1/2 bx)² = (2ax)² + 2 * 2ax * 1/2bx + (1/2bx)² =
= 4a²x² + 4/2abx² + 1/4b²x² =
= 4a²x² + 2abx² + 1/4b²x²
User Manolis Karamanis
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