Question

Rationalize the denominator of sqrt -9 / (4-7i) - (6-6i) ...?

Answer 1

√(- 9 ) / (( 4 - 7 i ) - ( 6 - 6 i )) = 3 i / ( 4 - 7 i - 6 + 6 i ) =
= 3 i / ( - 2 - i ) = - 3 i / ( 2 + i ) =

`= (-3i)/(2 + i)* (2 - i)/(2 - i)= \\ = (-6i+3i ^(2) )/(2- i^(2) )= \\ = (-3-6i)/(2+1)= (-3-6i)/(3)=`
= - 1 - 2 i

Answer 2

-3-6i/5 is the answer it was also correct on the test ! :D