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You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.

Let x be the number of bratwursts and y the number of hamburgers. whiichs system of inequalities represents this situation?

Options:
x+y<=40 1.35x+1.2y>=175
x+y<=40 1.35x+1.2y<=175
x+y>=120 1.35x+1.2>=175
x+y>=120 1.35x+1.2<=175
...?

2 Answers

4 votes

Answer:

Option D -
x+y\geq 120 ,
1.35x + 1.2y \leq 175

Explanation:

Given : You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.

To find : Which system of inequalities represents this situation?

Solution :

Let x be the number of bratwursts and y the number of hamburgers.

You want at least three bratwursts or hamburgers for each of your 40 guests.

i.e, you want at least
3*(40)=120 bratwursts or hamburgers.

We can write the equation as,

Number of bratwursts + number of hamburgers at least 120


x+y\geq 120

Bratwursts cost $1.35 each and hamburgers cost $1.2 each. Your budget is $175.

We can write equations as ,

Cost of bratwursts + cost of hamburgers at most 175


1.35x + 1.2y \leq 175

Therefore, The system of linear equation form is
x+y\geq 120,
1.35x + 1.2y \leq 175

Hence, Option D is correct.

User Luc Bloom
by
8.1k points
2 votes
x+y>=120 1.35x+1.2<=175

Is the logical interpretation of this scenario.
User Axxis
by
8.1k points
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