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The inverse sine of sin(2pi/3) = 120degrees, correct? ...?

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\sin{ (2\pi)/(3)} = ( √(3) )/(2) \\ \\ \sin{ (\pi)/(3)} = ( √(3) )/(2) \\ \\ - (\pi)/(2) \leq \arcsin{ x} \leq (\pi)/(2) \\ \\ \arcsin{(\sin{ (2\pi)/(3)})}=\arcsin{( ( √(3) )/(2) )}=(\pi)/(3)
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