Question

Find the discriminant of the following equation.
4x2 + 16x + 16 = 0 ...?

Answer 1

The discriminant is 0.

Explanation:

Since, the discriminant of a quadratic equation
`ax^2+bx+c=0` is,

`D=b^2-4ac`

Here, the given equation is,

`4x^2+16x+16=0`

By comparing,

a = 4, b = 16 and c = 16,

Hence, the discriminant of the given equation is,

`16^2-4* 4* 16`

`=256 - 256`

`=0`

Answer 2

To find the discriminant of the following equation you have to remember tha main formula : ax^2 +bx + c and the one for discriminant is b^2 -4ac
So, now we can solve it
`16^2 -4(16)(4) = 4^2-4(4)`

`(4^2)^2 -4(4)(4)(4)-4^2 +4(4) = 0`

`4^4 - 4^4 = 0`
`16^2-4*4*16=0` , so the discriminants is 0 :)
Hope it's clear!