Question

Suppose a treadmill has an average acceleration of 4.7 x 10^-3. A) how much does its speed change after five min? B )If the treadmill's initial speed is 1.7 m/s ,what will it's final speed be?

Answer 1

Step-by-step explanation:

Given that,

Acceleration of the treadmill,
`a=4.7* 10^(-3)\ m/s^2`

Time, t = 5 min = 300 s

Acceleration is given by :

`a=(v-u)/(t)`

(a) (v-u) is the change in speed.

`v-u=a* t`

`v-u=4.7* 10^(-3)* 300`

`v-u=1.41\ m/s`

So, the change in speed of the treadmill is 1.41 m/s.

(b) Initial speed of the treadmill, u = 1.7 m/s

The final speed is given by using equation as :

`v=u+at`

`v=1.7+4.7* 10^(-3)* 300`

v = 3.11 m/s

Hence, this is the required solution.