Question

Find a polynomial of degree n that has the given zeros. (There are many correct answers.)

zeroes: x=-1,5,7
degree: n=3

Answer 1

( x + 1 ) * ( x 5 ) * ( x - 7 ) =
= ( x² - 5 x + x - 5 ) * ( x - 7 ) =
= ( x² - 4 x - 5 ) * ( x - 7 ) =
= x³ - 7 x² - 4 x² + 28 x - 5 x + 35
Answer:
P ( x ) = x³ - 11 x² + 23 x + 35