1 Answer

Mesco · Answer 1 · 2017-10-17T07:10:56+0000

the solution is

L = S(ln (cos x))'dx = S(-sinx / cosx)dx =
0 < x < pi/4 0 < x < pi/4
let be U=cosx dU= -sinxdx
so
S(-sinx / cosx)dx = SdU/U = LnU =0-1/2ln2-ln2 =1/2)Ln2
0 < x < pi/4 1>U>sqrt 2/2 1>U>sqrt 2/2

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