Question

A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver sees a small gap between a van and an 18-wheel truck and accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 25.0 m/s when it reaches the end of the ramp, which has length 129 m.

What is the acceleration of the car?

Answer 1

So what we can do is use the next formula
(Vf)^2=(Vo)^2+2ad
So when we replace the data into the formula it goes (25)^2 = o^2 + 2(129)a
625 = 258a
a = 2.42 distance/time/time

I hope this helps you