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If sec 2A = 1/sin 13A, determine the angle A in degrees.

a. 5°
b. 6°
c. 3°
d. 7°

User Mineroot
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1 Answer

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sec 2 A = 1 / cos 2 A
1 / cos 2 A = 1 / sin 13 A
cos 2 A = sin 13 A
2 A = 90° - 13 A
2 A + 13 A = 90°
15 A = 90°
A = 90° : 15
Answer:
B ) A = 6°
User Aaronburrows
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7.3k points