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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Find the velocity when t = 1.
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May 4, 2017
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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Find the velocity when t = 1.
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Kturney
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y = 42t - 16t^2
velocity = vt = dy/dt
= 42 - 32t
v(1) = 42 - 32
= 10 ft/s
Hope this helps
Hridoy
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May 9, 2017
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