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Solve 2x+3y=10 and 3x-4y=-2

Solve 2x+3y=10 and 3x-4y=-2-example-1
User Anushree
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5 votes
the answer is (2,2) by addition
User Anders Branderud
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The solution to the system of equations 2x + 3y = 10 and 3x - 4y = -2 is x = 2 and y = 2.

Given the system of equations in the question:

2x + 3y = 10

3x - 4y = -2

To determine the solution to the system of equations, we can use the elimination method:

2x + 3y = 10

3x - 4y = -2

Multiply the first equation by 4 and the second equation by 3:

We have:

8x + 12y = 40

9x - 12y = -6

Now, we add the two equations.

We have:

17x + 0 = 34

x = 34/17

x = 2

Now, plug x = 2 into the first equation and solve for y:

2x + 3y = 10

2(2) + 3y = 10

4 + 3y = 10

3y = 10 - 4

3y = 6

y = 6/3

y = 2

Therefore, the value of x is 2 and the value of y is 2.

User GrumpyCanuck
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