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A study of college football games shows that the number of holding penalties assessed has a mean of 2.3 penalties per game and a standard deviation of 1.1 penalties per game.What is the probability that, for a sample of 40 college games to be played next week, the mean number of holding penalties will be 2.35 penalties per game or more?Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

User SwankTheTank
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1 Answer

15 votes
15 votes

We know:


\begin{gathered} \bar{x}=2.35 \\ S=1.1 \\ n=40 \\ \mu=2.3 \end{gathered}

The probability is:


t=\frac{\bar{x}-\mu}{(s)/(√(n))}=(2.3-2.35)/((1.1)/(√(40)))=0.2875

Then, from the normal distribution table:


\begin{gathered} 0.28\rightarrow0.6103 \\ 0.29\rightarrow0.6141 \end{gathered}

Now we compute the values in the calculator for the obtained value:


0.2875\rightarrow0.613

The probability is 0.613.

User Arcanox
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