Question

What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg

of water?
A. 0.33 mol/kg
B. 12 mol/kg
C. 3 mol/kg
D. 2 mol/kg

Answer 1

The molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water is calculated by dividing the moles of solute (NaOH) by the kilograms of solvent (water), resulting in a molality of 0.33 mol/kg, which is option A.

Step-by-step explanation:

The molality of a solution is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we use the formula:

Molality (m) = moles of solute / kilograms of solvent

In this case, we have 2 moles of NaOH dissolved in 6 kg of water. Plugging these values into the formula yields:

Molality (m) = 2 moles NaOH / 6 kg water = 0.33 mol/kg

Therefore, the molality of the solution is 0.33 mol/kg, which corresponds to option A.

Answer 2

The molality of a solution : m = 0.33 mol/kg

Further explanation

Given

2 moles of NaOH in 6 kg of water

Required

The molality

Solution

Molality shows how many moles are dissolved in every 1000 grams of solvent.

m = n x (1000/p)

m = Molality

n = number of moles of solute

p = solvent mass (grams)

Input the value :

solute : NaOH

solvent : water

m = 2 moles : 6 kg

m = 0.33 mol/kg