Question

A spinner is divided into 20 equal sections. what is the probability of the spinner's pointer landing on section 5?

Answer 1

Answer:
`(1)/(20)`

Explanation:

Given : The number of equal sections : 20

Then the probability of the spinner's pointer landing on each section will be :-

`\frac{\text{One}}{\text{Total sections}}\\\\=(1)/(20)`

Since , the probability of landing the spinner's pointer at any section is equal.

Therefore, the probability of the spinner's pointer landing on section 5
`=(1)/(20)`

Answer 2

1/20 would be the correct answer