97.4k views
4 votes
∑from 1to infinity of n^2* e^-2n

User Seephor
by
8.6k points

1 Answer

4 votes
∑ from 1 to infinity of n^2* e^(-2n) = (e^2 + e^4)/(e^2 - 1)^3 = 0.23768
User Vishesh Handa
by
8.5k points

Related questions

asked Apr 20, 2024 78.4k views
NiBE asked Apr 20, 2024
by NiBE
7.9k points
1 answer
3 votes
78.4k views
1 answer
2 votes
67.0k views
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories