Question

When the quadratic formula is applied to 2x^2 + 3x - 4 = 0, determine the numerator of thesimplified answer.

Answer 1

Given:

A quadratic equation is given as

`2x^2+3x-4=0`

Required:

Apply quadratic formula

Step-by-step explanation:

we have given hat

`2x^(2)+3x-4=0`

now compare the given equation with

`ax^2+bx+c=0`

and we get

`\begin{gathered} a=2 \\ b=3 \\ c=-4 \end{gathered}`

the roots are given as

`x=\frac{-b\pm\sqrt[\placeholder{⬚}]{b^2-4ac}}{2a}`
`\begin{gathered} =(-3\pm√(3^2-4*2*-4))/(2*2) \\ =\frac{-3\pm\sqrt[\placeholder{⬚}]{41}}{4} \end{gathered}`

Final answer:

`\begin{gathered} x_1=\frac{-3+\sqrt[\placeholder{⬚}]{41}}{4},x_2=\frac{-3-\sqrt[\placeholder{⬚}]{41}}{4} \\ \end{gathered}`