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Find the limit
lim t approaches 0 (tan(9t)/(sin(3t)

1 Answer

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u can use the property that tanx/x and sinx/x is 1 wen x->0. so now for tan(9x) , multiply and divide by 9x.similarly for sin3x,by 3x. so u get 9x/3x=3
User JacobJ
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