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Does (lnk)/(k^3), where as k starts at one and continues on to infinity, converge? ...?

Does (lnk)/(k^3), where as k starts at one and continues on to infinity, converge? ...?
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Does (lnk)/(k^3), where as k starts at one and continues on to infinity, converge? ...?

User Ryman Holmes
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Yes. The numerator does not increase as fast as the denominator increases, causing the function's value to decrease with every subsequent increase in the value of k. This causes the function to converge at a point.
User Russel
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