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Use implicit differentiation to find dy/dx: xe^y-ye^x=1
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Use implicit differentiation to find dy/dx: xe^y-ye^x=1
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Jan 16, 2017
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Use implicit differentiation to find dy/dx:
xe^y-ye^x=1
Mathematics
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Murli
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Use product rule d/dx fg = f'g + fg' and rearrange the terms for dy/dx to determine the correct answer!
x(e^y)(dy/dx) + e^(y) - ye^(x) - (dy/dx)e^(x) = 0
(dy/dx)(xe^y - e^x) = ye^x - e^y
Hence, dy/dx = (ye^x - e^y)/(xe^y - e^x)
I hope this helps!
DanielLC
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Jan 18, 2017
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xe^ydy/dx + e^y - ye^x - e^xdy/dx = 0
(xe^y - e^x)dy/dx = ye^x - e^y
dy/dx = (ye^x - e^y)/(xe^y - e^x)
Zubko
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Jan 22, 2017
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