Question

Quadrilateral EFGH has coordinates E(2b,b) F(3b,2b) G(b,0) and H(0,0).

Find the Midpoint of GF.
Answer choices
A) (b,b)
B) (0,b)
C) (2b,b)
D) (b,2b).

Answer 1

F(3b,2b) G(b,0)
midpoint of GF would be [(x1+x2)/2 , (y1+y2)/2]

= [4b/2 , 2b/2]
= [2b, b]
Therefore C is the answer.

Answer 2

C)(2b,b)

Explanation:

We are given that a quadrilateral EFGH whose coordinates are E(2b,b),F(3b,2b),G(b,0) and H(0,0).

We have to find the midpoint of GF.

Midpoint formula :

`x=(x_1+x_2)/(2),y=(y_1+y_2)/(2)`

We have
`x_2=3b,x_1=b,y_2=2b,y_1=0`

Using the formula

Then, we get

Midpoint of GF,
`x=(3b+b)/(2)=2b, y=(2b+0)/(2)=b`

Hence, the midpoint of GF=(2b,b)

Answer:C)(2b,b)