Question

Quadrilateral EFGH has coordinates E(a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of HG.

A (2a, 0)
B (a, 2a)
C (a, a)
D (a, 0)

Answer 1

Coordinates are: H ( 0, 0 ) and G ( 2 a, 0 ).
Coordinates of the midpoint are:
x = ( x 1 + x 2 ) / 2
y = ( y 1 + y 2 ) / 2
The midpoint of HG:
x = ( 0 + 2 a ) / 2 = 2 a / 2 = a
y = ( 0 + 0 ) / 2 = 0 / 2 = 0
Answer:
D ) ( a, 0 )

Answer 2

Midpoint of HG = ((0 + 2a)/2, (0 + 0)/2) = (2a/2, 0/2) = (a, 0)
option D is the correct answer.