208k views
1 vote
Find the exact positive value of c if the area between the graph of y=x^2-c^2 and the x -axis is 36.

User Sudhin
by
7.7k points

1 Answer

4 votes
If the area between the graph of y = x^2 - c^2 and the x-axis is 36, then

\int\limits^c_(-c) {(x^2-c^2)} \, dx =36\\ (x^3)/(3)-c^2x \left \} {{c} \atop {-c}} \right. =36\\(c^3)/(3)-c^3+(c^3)/(3)-c^3=36\\(-4c^3)/(3)=36\\c^3=-27\\c=-3
Therefore, the exact positive value of c is 3.
User Headuck
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories