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3 votes
Find
dy/du, du/dx, and dy/dx

y= u^2 , u=4x+7

User SKG
by
8.2k points

2 Answers

4 votes
y=u² (du/dx[u^n]=n(u^(n-1))u`)
dy/du=2u(u´)=2u

u=4x+7
du/dx=4

dy/dx=(dy/du)(du/dx)=2u(4)=2(4x+7)(4)=8(4x+7)

Answer:
dy/du=2u
du/dx=4
dy/dx=8(4x+7)
User Nate K
by
7.7k points
4 votes
dy/dx =2u
du/dx==4

and
dy/dx= (dy/du)(du/dx)
=2u(4)
= 8u
User Bmcculley
by
7.9k points

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