Question

The sum of 5 consecutive integers is 110.

Answer 1

To find the first integer, let's represent the integers with variable x
x+(x+1)+(x+2)+(x+3)+(x+4)=110 x+1=20+1=21
5x+10=110 x+2=20+2=22
5x+10-10=110-10 x+3=20+3=23
5x=100 x+4=20+4=24
5x/5=100/5
x=20 20+21+22+23+24=110

Answer 2

They would be 20, 21, 22, 23, and 24