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115 mL of a 2.35 M potassium

fluoride (KF) solution is diluted with 1.28 L of water. What is the new concentration in molarity?
? M KF

2 Answers

7 votes

Answer: 0.194

Step-by-step explanation:

User Story Ks
by
4.6k points
2 votes

The new concentration : = 0.194 M

Further explanation

Given

115 mL(0.115 L) of a 2.35 M Potassium fluoride (KF)

1.28 L of water

Required

The new concentration

Solution

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = volume of the solution after dilution

V₂=0.115 + 1.28 = 1.395 L

Input the value :

M₂ = (M₁V₁)/V₂

M₂ = (2.35 x 0.115)/1.395

M₂ = 0.194

User Kadeem
by
4.2k points