Question

URGENT!!!!!

Determine the discriminant for the quadratic equation –3 = x2 + 4x + 1. Based on the discriminant value, how many real number solutions does the equation have?

Discriminant = b2 – 4ac


____ real number solutions

Answer 1

Discriminant = b^2 - 4ac = 4^2 - 4*1*4 = 0

There are 2 real solutions

They are x = -2 (duplicity 2).

Explanation:

Answer 2

The equation -3=x^2+4x+1 can be rearranged into x^2+4x+4=0, you should be able recognise that this is an equation of the form ax^2+bx+c (where a, b, and c are constants). The question tells you that the discriminant of an equation of form ax^2+bx+c is equal to b^2-4ac, therefore after rearranging the equation you simply substitute the numbers in:

a=1 b=4 c=4
b^2-4ac=(4)^2-4x(1)x(4)=16-16=0

Therefore the discriminant value is 0.

To determine the amount of real solutions an equation has you look at the discriminant, if the discriminant is less than 0 there are no real solutions, if the discriminant is equal to 0 there is one solution, and if the discriminant is more than 0 there are 2 solutions. therefore as our discriminant is equal to - there is 1 real solution.