2 Answers

Ambiguousmouse · Answer 1 · 2017-06-10T09:43:26+0000

Answer:

$x=-5\text{ or }x=1$ .

Explanation:

We have been given a quadratic equation
4(x+2)^2=36 . We are asked to find the solutions for our given equation.

First of all, we will divide both sides of our given equation by 4 as shown below:

(4(x+2)^2)/(4)=(36)/(4)

(x+2)^2=9

Now, we will take square root of both sides of our equation.

$√((x+2)^2)=\pm √(9)$

$√((x+2)^2)=\pm √(3^2)$

Using radical rule
$\sqrt[n]{a^n}=a$ , we will get:

$x+2=\pm 3$

Upon subtracting 2 from both sides of our given equation, we will get:

$x+2-2=-2\pm 3$

$x=-2\pm 3$

Now, we will write two equivalent equations to our equation as:

$x=-2-3\text{ or }x=-2+3$

$x=-5\text{ or }x=1$

Therefore, the solutions for our given quadratic equation are
$x=-5\text{ or }x=1$ .

Please log in or register to add a comment.