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5=P (-2, 4)43If P = (-2, 4),then find:Ry=1 (P)2y=11 2345 -4 -3 -2 -1 0-1([?], [])-2-3-4ាEnter

5=P (-2, 4)43If P = (-2, 4),then find:Ry=1 (P)2y=11 2345 -4 -3 -2 -1 0-1([?], [])-2-3-4ាEnter-example-1
User Mcwitt
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1 Answer

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10 votes

We need to find the reflection of point P across the line y = 1.

Reflection across the line y = k transforms the point (x,y) into (x, 2k - y).

Applying this rule to the point P(-2, 4) with the line y = 1 (k = 1), we get:

P(-2, 4) → (-2, 2x1 - 4) → P'(-2, -2)

User Shanimal
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