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121+b^2=12.1^2 What is the value of b^2?
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121+b^2=12.1^2
What is the value of b^2?

User Damusnet
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1 Answer

2 votes

121 + b^2 = 12.1^2
Square 12.1, and subtract 121 from both sides.

b^2 = 146.41 - 121
Complete the subtraction on the right side.

b^2 = 25.41
This is the solution.


b^2 = 25.41
User Vfn
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