Question

How do I write an equation in slope intercept form that passes through point (-7,6) and is perpendicular to line with slope -3/7

Answer 1

When two lines are perpendicular, their slopes are negative reciprocals.

That means that the slope of one line is -1/(slope of the other line).

You have the slope of one line. It's -3/7 .

So the slope of any line perpendicular to that one is 7/3 .

Now you know the slope of the new line, and you know one point on it.

Slope = 7/3
Through the point (-7, 6)

I'm pretty sure you know how to do the rest.
The trick was knowing how to find the slope of the new line.