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What is an equation of the line through (0,-3) with slope 2\5

User Erictrigo
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m=2/5 , (0,3)
use y= mx+c , find c first.
-3 = (2/5) 0 + c
c = -3
Thus the equation will be y=(2/5)x - 3.
or in some case,
(y1-y)=m(x1-x)
(-3-y)=(2/5)(0-x)



User Dima Tisnek
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