Question

You push a block at a constant speed across a horizontal surface that has a friction force of 2N. Your push is 2N and the displacement of the block is 10 m. How much total work is done on the block?

Answer 1

0 J

Explanation:

Given:

Applied force (F) = 2 N

Friction force (Ff) = -2 N

Distance (d) = 10 m

The work is equivalent to the product between the force and the distance, therefore, we calculate it in the following way:

`\begin{gathered} \text{For the case of the applied force} \\ \\ W_(app)=F\cdot d \\ \\ \text{ We replacing} \\ \\ W_(app)=10\cdot2 \\ \\ W_(app)=20\text{ J} \\ \\ \text{ For the case of the friction force} \\ \\ W_(fric)=F_f\cdot d \\ \\ \text{We replac}\imaginaryI\text{ng} \\ \\ W_(fric)=-10\cdot2 \\ \\ W_(fric)=\text{ -20 J} \\ \\ \text{ Therefore, the total work would be:} \\ \\ W=W_(app)+W_(fric) \\ \\ W=20-20 \\ \\ W=0\text{ J} \end{gathered}`

Which means that the total work is equal to 0 joules