Question

3. A sample of neon gas has a volume of 1.2 L at 28.5°C. What will the volume be at 125°C it the

pressure remains constant?

Answer 1

1.58L

Step-by-step explanation:

Given parameters:

Initial volume = 1.2L

Initial temperature = 28.5°C = 28.5 + 273 = 301.5K

Final temperature = 125°C = 125 + 273 = 398K

Unknown:

New volume = ?

Solution:

Volume and temperature relationship is resolved using the Charles's law.

The law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the the pressure is constant".

So;

`(V1)/(T1)` =
`(V2)/(T2)`

V1 is the initial volume

T1 is the initial temperature

V2 is the new volume

T2 is the new temperature

`(1.2)/(301.5)` =
`(V2)/(398)`

301.5V2 = 477.6

V2 = 1.58L