Question

What equation is graphed in this figure?

y−3=13(x+1)y−3=13(x+1)

y−5=3(x−1)y−5=3(x−1)

y−4=−13(x+2)y−4=−13(x+2)

y+2=−3(x−1)

Answer 1

x^2+y^2=9 (an equation of a circle with a radius of 3)sin(x)+cos(y)=0.52x-3y=1cos(x^2)=y(x-3)(x+3)=y^2y=x^2

Answer 2

The Answer would be B. y−5=3(x−1)y−5=3(x−1)

Good Luck =D