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What equation is graphed in this figure? y−3=13(x+1)y−3=13(x+1) y−5=3(x−1)y−5=3(x−1) y−4=−13(x+2)y−4=−13(x+2) y+2=−3(x−1)
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Jul 17, 2017
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What equation is graphed in this figure?
y−3=13(x+1)y−3=13(x+1)
y−5=3(x−1)y−5=3(x−1)
y−4=−13(x+2)y−4=−13(x+2)
y+2=−3(x−1)
Mathematics
middle-school
Gvo
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x^2+y^2=9 (an equation of a circle with a radius of 3)sin(x)+cos(y)=0.52x-3y=1cos(x^2)=y(x-3)(x+3)=y^2
y=x^2
DGrady
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Jul 20, 2017
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The Answer would be B. y−5=3(x−1)y−5=3(x−1)
Good Luck =D
Eryn
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Jul 23, 2017
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