What equation is graphed in this figure? y−3=13(x+1)y−3=13(x+1) y−5=3(x−1)y−5=3(x−1) y−4=−13(x+2)y−4=−13(x+2) y+2=−3(x−1)

asked Jul 17, 2017 234k views

4 votes

What equation is graphed in this figure?

y−3=13(x+1)y−3=13(x+1)

y−5=3(x−1)y−5=3(x−1)

y−4=−13(x+2)y−4=−13(x+2)

y+2=−3(x−1)

by Gvo

7.6k points

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2 votes

x^2+y^2=9 (an equation of a circle with a radius of 3)sin(x)+cos(y)=0.52x-3y=1cos(x^2)=y(x-3)(x+3)=y^2y=x^2

DGrady answered Jul 20, 2017

7.8k points

6 votes

The Answer would be B. y−5=3(x−1)y−5=3(x−1)

Good Luck =D

Eryn answered Jul 23, 2017

by Eryn

8.4k points

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