Step 1
The reaction:
CH4 + 2O2 => CO2 +2H2O (already balanced)
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Step 2
Information needed:
The molar mass of CH4 (16.0 g/mol) and H2O (18.0 g/mol)
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Step 3
By stoichiometry:
1 mol CH4 = 16.0 g
1 mol H2O = 18.0 g
Procedure:
16.0 g CH4 -------- 2 x 18.0 g H2O
100. g CH4 -------- X
X = 100. g CH4 x 2 x 18.0 g H2O/16.0 g CH4 = 225. g H2O
Answer: 225. g H2O