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Divide a 5-inch line into two parts so that one part (a) 2 1/4 inches shorter than the other; (b) 3 times the other.

2 Answers

3 votes

Answer:

We have to divide 5-inch line into two parts so that one part (a) 2 1/4 inches or 2.25 inches shorter than the other; (b) 3 times the other

We can write this statement as :

(a)
x+(x-2.25)=5

Solving this we get


2x=5+2.25


2x=7.25

x = 3.625 inches

And the other part will be =
5-3.625=1.375 inches

(b) As we have x+y=5

We have to find two parts where one is 3 times the other. This means we have to find x=3y

So, we have
3y+y=5


4y=5

y = 1.25 inches

Other part x is
5-1.25=3.75 inches

User Martin Golpashin
by
6.7k points
4 votes
part a), solve this system of equations:
x + y = 5
x - y = 2.25
2x = 7.25
x = 3.625
y = 1.375

part b), solve this system of equations:
x + y = 5
x = 3y
y = 1.25
x = 3.75
User Rick Ballard
by
6.7k points
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