Question

How to solve and answer.vo = 250 m/s.Angle = 40 degrees.

Answer 1

From the given graph, let's find the time it takes the projectile to reach its maximum height.

Given:

θ = 40 degrees

Initial velocity, vo = 250 m/s.

To find the time it takes the projectile to reach maximum height, apply the formula:

`v_y=v_o\sin \theta-gt`

Where:

vy is the final velocity at maximum height = 0 m/s

vo is the initial velocity

g is acceleration due to gravity = 9.8 m/s²

`0=v_0\sin \theta-gt`

Rewrite the formula for the time, t:

`t=(v_0\sin \theta)/(g)`

Input values into the formula and solve for t:

`\begin{gathered} t=(250\sin 40)/(9.8) \\ \\ t=(160.67)/(9.8) \\ \\ t=16.4\text{ s} \end{gathered}`

Therefore, the time it takes the projectile to reach its maximum height is 16.40 seconds.

ANSWER:

a. 16.40 s

a. 16.40