23,846 views
22 votes
22 votes
M is the midpoint of JK. The coordinates of J are (6, 3) and the coordinates of M are (-3, 4) find the coordinates of K.

M is the midpoint of JK. The coordinates of J are (6, 3) and the coordinates of M-example-1
User Guy Levin
by
2.5k points

1 Answer

11 votes
11 votes

Given the line segment JK, point M is its midpoint, this means that it divided the line segment in two smaller segments of equal size:

JM=MK

JK= JM+MK

Since the distance from J to M is the same as the distance from M to K, first step is to calculate said distance:


d_(My)=y_M-y_J=4-3=1
d_(Mx)=X_J-X_M=6-(-3)=6+3=9_{}

The distance between points J and M is 1 unit over the y-axis and 9 units over the x-axis, this is the same distance point K is from point M.

If you graph both points in the cartesian system and link them with a line, you'll see that point K is located in the fourth quadrant.

So to determine its coordinates, you have to add the calculated distance to the y- coordinate of M:


y_K=y_M+d_(My)=4+1=5

And subtract the distance over the x-axis to the x-coordinate of M


x_K=y_M-d_(Mx)=-3-9=-12

The coordinates of K are (-12,5)

The correct option is the first one.

User Cedric Zoppolo
by
3.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.