Question

For which value of a are the graphs of –4 = 3x + 6y and ax – 8y = 12 parallel?

Answer 1

The answer is A) a=-4

Explanation:

Answer 2

The value of a is -4.

Explanation:

Since, two lines
`a_1 x+b_1 y=c_1` and
`a_2 x+b_2 y=c_2` are called parallel lines,

If
`(a_1)/(a_2)=(b_1)/(b_2)\\eq (c_1)/(c_2)`

If 3x + 6y = 4 and ax-8y = 12 are parallel lines,

Then, by the above property,

`(3)/(a)=(6)/(-8)\\eq (4)/(12)`

`\implies (3)/(a)=(6)/(-8)`

By cross multiplication,

`-24 = 6a`

`\implies -4=a` ( Dividing both terms by 6}

Hence, the value of a is -4 for which 4 = 3x + 6y and ax – 8y = 12 are parallel.